# In triangle ABC, angle C is 90. BC = 9. Sin A = 0.75. Find AB

September 20, 2021 | education

| Given: right-angled triangle ABC;

angle C = 90;

sin A = 0.75;

BC = 9;

Find: AB -?

Solution:

1) Consider a right-angled triangle ABC. The sine of the angle in a right-angled triangle is equal to the ratio of the opposite leg to the hypotenuse. Hence:

sin A = CB / AB;

AB = BC / sin A;

AB = 9: 0.75;

AB = 900 * 75;

AB = 12.

Answer: AB = 12.

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